If the equation of a transverse wave is Y = 2 | vedclass

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(A) The standard equation of a transverse wave is given by $Y = a \sin(kx - \omega t)$.Comparing the given equation $Y = 2 \sin(kx - 2t)$ with the sta

Vedclass · Accepted Answer

$4$

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(A) The standard equation of a transverse wave is given by $Y = a \sin(kx - \omega t)$.Comparing the given equation $Y = 2 \sin(kx - 2t)$ with the standard form,we get the amplitude $a = 2$ and the angular frequency $\omega = 2$.The particle velocity $v_p$ is the derivative of displacement $Y$ with respect to time $t$:$v_p = \frac{dY}{dt} = \frac{d}{dt} [2 \sin(kx - 2t)] = 2 \cos(kx - 2t) 	imes (-2) = -4 \cos(kx - 2t)$.The maximum particle velocity is given by the magnitude of the coefficient of the cosine term:$v_{max} = a \omega = 2 	imes 2 = 4 \, units$.

If the equation of a transverse wave is $Y = 2 \sin(kx - 2t)$,then the maximum particle velocity is .... $units$.

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