If the following quadratic equation has two equal and real roots,then find the value of $k$: $(k+1)x^2 - 2(k-1)x + 1 = 0$.

  • A
    $0$ and $3$
  • B
    $1$ and $2$
  • C
    $7$ and $-3$
  • D
    $3$ and $-4$

Explore More

Similar Questions

Solve the following equation using the method of factorization and write its solution set: $x - \frac{1}{x} - \frac{45}{14} = 0$; $x \neq 0$.

The product of the digits of a two-digit number is $14$. The number obtained by interchanging the digits is $45$ more than the original number. Find the original number.

Difficult
View Solution

If the following quadratic equation has two equal and real roots,then find the value of $k$: $16x^{2} - 40x + \frac{k-1}{2} = 0$.

Find the roots of the quadratic equation by using the quadratic formula: $-x^{2}+7x-10=0$.

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $3x^{2} - 18x + 27 = 0$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo