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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by $K_{max} = h
u - \Phi

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remains same.

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by $K_{max} = h
u - \Phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident radiation,and $\Phi$ is the work function of the metal.Since the stopping potential $(V_{s})$ is related to the maximum kinetic energy by the relation $eV_{s} = K_{max}$,we have $eV_{s} = h
u - \Phi$.This equation shows that the stopping potential $(V_{s})$ depends only on the frequency $(
u)$ of the incident radiation and the work function $(\Phi)$ of the metal surface.Intensity of light affects the number of photons incident per unit area per unit time,which in turn affects the number of photoelectrons emitted (photoelectric current),but it does not affect the maximum kinetic energy of the individual photoelectrons.Therefore,if the frequency $(
u)$ is kept constant,the stopping potential $(V_{s})$ remains the same regardless of changes in the intensity of the incident light.

If the frequency of incident radiation is kept constant and the experiment is repeated by using incident light of different intensities,then the stopping potential $(V_{s})$

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