If the function $f(x) = \begin{cases} \frac{(e^{kx} - 1) \tan kx}{4x^2}, & x \neq 0 \\ 16, & x = 0 \end{cases}$ is continuous at $x = 0$,then $k = . . . . . .$.

  • A
    $\pm \frac{1}{8}$
  • B
    $\pm 4$
  • C
    $\pm 2$
  • D
    $\pm 8$

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