If the general formula of oxime and semicarba | vedclass

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(C) The general structure for these derivatives is $C=N-Z$.For oximes,the derivative is formed by the reaction of a carbonyl compound with hydroxylami

Vedclass · Accepted Answer

$OH, \quad NHCONH_2$

Vedclass · Answer

(C) The general structure for these derivatives is $C=N-Z$.For oximes,the derivative is formed by the reaction of a carbonyl compound with hydroxylamine $(NH_2OH)$. Thus,the group $Z$ attached to the nitrogen is $-OH$.For semicarbazones,the derivative is formed by the reaction of a carbonyl compound with semicarbazide $(NH_2NHCONH_2)$. Thus,the group $Z$ attached to the nitrogen is $-NHCONH_2$.Therefore,for oxime $(I)$,$Z = -OH$ and for semicarbazone $(II)$,$Z = -NHCONH_2$.

If the general formula of oxime and semicarbazone is $C=N-Z$,what is '$Z$' in oxime $(I)$ and semicarbazone $(II)$?

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