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(A) The volume of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$,where $r$ is the radius and $h$ is the height.Let the original volume be

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(A) The volume of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$,where $r$ is the radius and $h$ is the height.Let the original volume be $V_1 = \frac{1}{3} \pi r^2 h$.If the height is doubled,the new height $h' = 2h$.The new volume $V_2 = \frac{1}{3} \pi r^2 (2h) = 2 	imes (\frac{1}{3} \pi r^2 h) = 2V_1$.The increase in volume is $V_2 - V_1 = 2V_1 - V_1 = V_1$.The percentage increase is given by $\frac{	ext{Increase}}{	ext{Original Volume}} 	imes 100 = \frac{V_1}{V_1} 	imes 100 = 100 \%$.

If the height of a cone is doubled,then its volume is increased by (in $\%$)

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