If the kinetic energy (K.E.) of a particle is | vedclass

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(D) The relationship between momentum $(P)$ and kinetic energy $(E)$ is given by the formula: $P = \sqrt{2mE}$.Since mass $(m)$ is constant,we have $P

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Increase $\sqrt{2}$ times

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(D) The relationship between momentum $(P)$ and kinetic energy $(E)$ is given by the formula: $P = \sqrt{2mE}$.Since mass $(m)$ is constant,we have $P \propto \sqrt{E}$.If the kinetic energy is doubled,the new kinetic energy $E' = 2E$.Therefore,the new momentum $P' = \sqrt{2m(2E)} = \sqrt{2} 	imes \sqrt{2mE} = \sqrt{2}P$.Thus,the momentum increases by a factor of $\sqrt{2}$.

If the kinetic energy $(K.E.)$ of a particle is doubled,then its momentum will

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