If the last four letters of the word CONCENTR | vedclass

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(D) The word is $CONCENTRATION$ (total $13$ letters).Step $1$: Divide the word into groups: $(C, O, N, C) (E, N) (T, R, A) (T, I, O, N)$.Step $2$: Rev

Vedclass · Accepted Answer

$R$

Vedclass · Answer

(D) The word is $CONCENTRATION$ (total $13$ letters).Step $1$: Divide the word into groups: $(C, O, N, C) (E, N) (T, R, A) (T, I, O, N)$.Step $2$: Reverse each group:- Last four $(T, I, O, N)$ reversed becomes $N, O, I, T$.- Next two $(T, R, A)$ reversed (Wait,the prompt says next two,then next three. Let's re-evaluate the grouping based on the word $CONCENTRATION$ ($13$ letters): $C, O, N, C, E, N, T, R, A, T, I, O, N$.- The last four are $T, I, O, N$. Reversed: $N, O, I, T$.- The next two (from the end,moving left) are $A, R$. Reversed: $R, A$.- The next three are $T, N, E$. Reversed: $E, N, T$.- The first four are $C, O, N, C$. Reversed: $C, N, O, C$.Step $3$: The new sequence is $NOIT + RA + ENT + CNOC = NOITRAENTCNOC$.Step $4$: Counting from the end (right to left),the $8$th letter is:$1(C), 2(O), 3(N), 4(C), 5(T), 6(N), 7(E), 8(R)$.The $8$th letter is $R$.

If the last four letters of the word $CONCENTRATION$ are written in reverse order,followed by the next two in reverse order,the next three in reverse order,and finally the first four in reverse order,which letter would be the eighth in the new arrangement,counting from the end?

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