If the length of the potentiometer wire is in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The potential gradient $k$ is defined as $k = V/L$,where $V$ is the potential difference across the wire and $L$ is the length of the wire.Given t

Vedclass · Accepted Answer

the null point is obtained at a larger distance.

Vedclass · Answer

(C) The potential gradient $k$ is defined as $k = V/L$,where $V$ is the potential difference across the wire and $L$ is the length of the wire.Given that $V$ is constant,if the length $L$ is increased,the potential gradient $k$ decreases.The null point is obtained when the potential drop across the balancing length $l$ equals the $EMF$ of the cell $E$,i.e.,$E = kl$.Since $E$ is constant and $k$ has decreased,the balancing length $l = E/k$ must increase.Therefore,the null point is obtained at a larger distance.

If the length of the potentiometer wire is increased by keeping the potential difference across the wire constant,then:

Similar Questions

Two cells,when connected in series,are balanced on $8 \; m$ on a potentiometer. If the cells are connected such that the polarity of one of the cells is reversed,they balance on $2 \; m$. The ratio of the $e.m.f.$'s of the two cells is:

In a potentiometer, the null point is received at the $7^{th}$ wire. If we now want to shift the null point to the $9^{th}$ wire, what should we do?

The potentiometer is best for measuring voltage,as

$A$ cell is connected to a potentiometer, and the balance point is obtained at a length of $2 \, m$. When a resistance of $5 \, \Omega$ is connected in parallel with the cell, the balance point is obtained at a length of $3 \, m$. What is the internal resistance of the cell in $\Omega$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module