If the line $\frac{x-3}{2}=\frac{y+5}{-1}=\frac{z+2}{2}$ lies in the plane $\alpha x+3y-z+\beta=0$,then the values of $\alpha$ and $\beta$ respectively are ....

  • A
    $\frac{3}{2}, \frac{13}{2}$
  • B
    $\frac{5}{2}, \frac{9}{2}$
  • C
    $-\frac{5}{2}, \frac{9}{2}$
  • D
    $\frac{5}{2}, \frac{11}{2}$

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