If the magnetic field inside a solenoid is B, | vedclass

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Question

(B) The magnetic energy density $(u_B)$ stored in a magnetic field $B$ is given by the formula: $u_B = \frac{B^2}{2\mu_0}$.We know that the speed of l

Vedclass · Accepted Answer

$\frac{\varepsilon_0 c^2 B^2}{2}$

Vedclass · Answer

(B) The magnetic energy density $(u_B)$ stored in a magnetic field $B$ is given by the formula: $u_B = \frac{B^2}{2\mu_0}$.We know that the speed of light in vacuum is $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$,which implies $c^2 = \frac{1}{\mu_0 \varepsilon_0}$.From this,we can express the permeability of free space as $\mu_0 = \frac{1}{\varepsilon_0 c^2}$.Substituting this value of $\mu_0$ into the energy density formula:$u_B = \frac{B^2}{2(1 / \varepsilon_0 c^2)}$$u_B = \frac{\varepsilon_0 c^2 B^2}{2}$.Therefore,the correct option is $B$.

If the magnetic field inside a solenoid is $B$,then the magnetic energy stored in it per unit volume is (where $c$ is the speed of light in vacuum and $\varepsilon_0$ is the permittivity of free space).

Similar Questions

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