If the mass number of an atom is A = 40 and i | vedclass

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(A) The number of electrons in a neutral atom is equal to the number of protons $(Z)$.Given electron configuration: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$.Tot

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$22, 18$

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(A) The number of electrons in a neutral atom is equal to the number of protons $(Z)$.Given electron configuration: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$.Total number of electrons $= 2 + 2 + 6 + 2 + 6 = 18$.Therefore,the number of protons $(Z)$ $= 18$.The mass number $(A)$ is the sum of protons and neutrons: $A = Z + N$.Given $A = 40$ and $Z = 18$,we have $40 = 18 + N$.Number of neutrons $(N)$ $= 40 - 18 = 22$.Thus,the number of neutrons is $22$ and the number of protons is $18$.

If the mass number of an atom is $A = 40$ and its electron configuration is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$,the number of neutrons and protons in its nucleus will be

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