If the mean of the data $7, 8, 9, 7, 8, 7, \lambda, 8$ is $8$,then the variance of the data is:

  • A
    $2$
  • B
    $\frac{7}{8}$
  • C
    $\frac{9}{8}$
  • D
    $1$

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Similar Questions

If the variance of the frequency distribution is $160$,then the value of $c \in N$ is
$X$ $c$ $2c$ $3c$ $4c$ $5c$ $6c$
$f$ $2$ $1$ $1$ $1$ $1$ $1$

In an experiment with $15$ observations on $x$,we have $\sum x^2 = 2830$ and $\sum x = 170$. One observation that was $20$ was found to be wrong and was replaced by the correct value $30$. The corrected variance is:

The outcome of each of $30$ items was observed; $10$ items gave an outcome $\frac{1}{2} - d$ each,$10$ items gave an outcome $\frac{1}{2}$ each,and the remaining $10$ items gave an outcome $\frac{1}{2} + d$ each. If the variance of this outcome data is $\frac{4}{3}$,then $|d|$ equals:

Find the variance of the sequence $a, a + d, a + 2d, \dots, a + 2nd$.

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View Solution

If $\sum_{i=1}^{n}(x_{i}-a)=n$ and $\sum_{i=1}^{n}(x_{i}-a)^{2}=na$,where $n, a > 1$,then the standard deviation of $n$ observations $x_{1}, x_{2}, \ldots, x_{n}$ is

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