If the moment of inertia of a thin circular ring about an axis passing through its edge and perpendicular to its plane is $I$, then the moment of inertia of the ring about its diameter is

$A$ thin rod has a length of $1 \ m$ and a mass of $0.6 \ kg$. The moment of inertia of the rod about an axis perpendicular to its length and passing through a point $20 \ cm$ from one end is ................... $kg \cdot m^2$ (the width of the rod is negligible).

The moment of inertia of a uniform ring of mass $M$ and radius $r$ about a tangent in its own plane is:

$A$ solid sphere and a disc of same mass $M$ and radius $R$ are kept such that their curved surfaces are in contact and their centers lie along the same horizontal line. The moment of inertia of the two-body system about an axis passing through their point of contact and perpendicular to the plane of the disc is

The moment of inertia of a thin uniform rod of length $L$ and mass $M$ about an axis passing through a point at a distance of $\frac{L}{3}$ from one of its ends and perpendicular to the rod is

$A$ thin wire of length $L$ has a uniform linear mass density $\rho$. It is bent into a circular loop with center $O$. Calculate the moment of inertia of the circular loop about the axis $XX'$ as shown in the figure.