If the number of turns in the coil of a galvanometer is decreased,then the resistance of the galvanometer:

With a resistance '$X$' connected in series with a galvanometer of resistance $100 \Omega$, it acts as a voltmeter of range $0 - 15 \text{ V}$. To double the range, a resistance of $1500 \Omega$ is to be connected in series with '$X$'. The value of '$X$' in $\Omega$ is

$A$ galvanometer of resistance '$G$' is shunted by a resistance of '$S$' ohm. To keep the main current in the circuit unchanged,the resistance to be put in series with the galvanometer is:

Two galvanometers $A$ and $B$ require currents of $4 \ mA$ and $7 \ mA$,respectively,to produce the same deflection of $20$ divisions. If $S_{A}$ and $S_{B}$ are their sensitivities,respectively,then:

$A$ galvanometer has resistance '$G$' and range '$V_g$'. How much resistance is required to read voltage up to '$V$' volt?

If only $2 \%$ of the main current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt connected to it will be: