If the percentage error in the radius of a circle is $3\%$, then the percentage error in its area is (in $\%$)

If the radius of a sphere is measured as $7 \text{ m}$ with an error of $0.02 \text{ m}$, then find the approximate error in calculating its volume. (in $\pi \text{ m}^3$)

Using differentials,find the approximate value of $(33)^{-\frac{1}{5}}$.

The approximate value of the function $f(x) = x^{3} - 3x + 5$ at $x = 1.99$ is

If $1^{\circ} = \alpha$ radians,then the approximate value of $\cos(60^{\circ} 1^{\prime})$ is

If an error of $0.02 \text{ cm}^2$ is found in the surface area of a sphere when its radius is measured as $10 \text{ cm}$, then the approximate error that occurs in the volume of the sphere, in cubic centimetres, is