If the planes 3x - 2y + 2z + 17 = 0 and 4x + | vedclass

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(A) Two planes $a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$ are perpendicular if and only if $a_1a_2 + b_1b_2 + c_1c_2 = 0$.Given

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$3$

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(A) Two planes $a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$ are perpendicular if and only if $a_1a_2 + b_1b_2 + c_1c_2 = 0$.Given the equations of the planes are $3x - 2y + 2z + 17 = 0$ and $4x + 3y - kz - 25 = 0$.Here,$a_1 = 3, b_1 = -2, c_1 = 2$ and $a_2 = 4, b_2 = 3, c_2 = -k$.Substituting these values into the condition for perpendicularity:$(3)(4) + (-2)(3) + (2)(-k) = 0$$12 - 6 - 2k = 0$$6 - 2k = 0$$2k = 6$$k = 3$.

If the planes $3x - 2y + 2z + 17 = 0$ and $4x + 3y - kz = 25$ are mutually perpendicular,then $k = $

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