If the potential of the inner shell of radius | vedclass

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(A) Let $Q_1$ be the charge on the inner shell of radius $r$ and $Q_2$ be the charge on the outer shell of radius $2r$.The potential at the surface of

Vedclass · Accepted Answer

$10$

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(A) Let $Q_1$ be the charge on the inner shell of radius $r$ and $Q_2$ be the charge on the outer shell of radius $2r$.The potential at the surface of the inner shell is given by:$V_{in} = \frac{kQ_1}{r} + \frac{kQ_2}{2r} = 10\,V$  --- $(1)$The potential at the surface of the outer shell is given by:$V_{out} = \frac{kQ_1}{2r} + \frac{kQ_2}{2r} = 5\,V$  --- $(2)$The potential at the centre of the shells is the sum of potentials due to both shells:$V_{centre} = \frac{kQ_1}{r} + \frac{kQ_2}{2r}$Comparing this expression with equation $(1)$, we see that the potential at the centre is exactly equal to the potential at the surface of the inner shell.Therefore, $V_{centre} = 10\,V$.

If the potential of the inner shell of radius $r$ is $10\,V$ and that of the outer shell of radius $2r$ is $5\,V$, then the potential at the centre will be....$V$

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