If the probability distribution of a random variable $X$ is as follows, then the variance of $X$ is
$\begin{array}{|c|c|c|c|c|}\hline X=x & 2 & 3 & 5 & 9 \\\hline P(X=x) & K & 2 K & 3 K^2 & K^2 \\\hline\end{array}$

  • A
    $\frac{61}{4}$
  • B
    $\frac{7}{2}$
  • C
    $12$
  • D
    $3$

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