If the product of the zeros of p(x) = ax^{2} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a quadratic polynomial $p(x) = ax^{2} + bx + c$,the product of the zeros is given by the formula $\frac{c}{a}$.Given the polynomial $p(x) = ax

Vedclass · Accepted Answer

$-3/2$

Vedclass · Answer

(C) For a quadratic polynomial $p(x) = ax^{2} + bx + c$,the product of the zeros is given by the formula $\frac{c}{a}$.Given the polynomial $p(x) = ax^{2} - 6x - 6$,we identify the coefficients as $A = a$,$B = -6$,and $C = -6$.The product of the zeros is given as $4$.Therefore,$\frac{C}{A} = 4$.Substituting the values,we get $\frac{-6}{a} = 4$.Solving for $a$: $4a = -6$,which implies $a = -\frac{6}{4} = -\frac{3}{2}$.Thus,the correct value of $a$ is $-\frac{3}{2}$.

If the product of the zeros of $p(x) = ax^{2} - 6x - 6$ is $4$,then $a = $ ............

Similar Questions

Divide $x^{4}-3 x^{2}+4 x+5$ by $x^{2}-x+1$.

State the degree of the given polynomial: $p(x) = 5x - 2x^2 + 3$

Divide $x^{4}+4 x^{3}-2 x^{2}-12 x+9$ by $x^{2}-2 x+1$.

The zeros of cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$; $a \neq 0, a, b, c, d \in R$ are $\alpha, \beta$ and $\gamma$; then $\alpha\beta + \beta\gamma + \gamma\alpha = \ldots$

Draw the graph of $p(x) = 2x - 5$ and find the zeros of this polynomial.

Vedclass Test Series

Exam Paper Generator

Online Exam Module