If the rate of reaction is given as frac{1}{3 | vedclass

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Question

(D) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is expressed as $-\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}

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$2Y + Z \rightarrow 3X$

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(D) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is expressed as $-\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}{dt} = \frac{1}{c} \frac{d[C]}{dt} = \frac{1}{d} \frac{d[D]}{dt}$.Given: $\frac{1}{3} \frac{d[X]}{dt} = -\frac{1}{2} \frac{d[Y]}{dt} = -\frac{d[Z]}{dt}$.This implies that $X$ is a product (positive sign) with a stoichiometric coefficient of $3$,and $Y$ and $Z$ are reactants (negative sign) with stoichiometric coefficients of $2$ and $1$ respectively.Thus,the reaction is $2Y + Z \rightarrow 3X$.

If the rate of reaction is given as $\frac{1}{3} \frac{d[X]}{dt} = -\frac{1}{2} \frac{d[Y]}{dt} = -\frac{d[Z]}{dt}$,the reaction can be represented as

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