If the ratio of the amplitude of two waves is | vedclass

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(C) The intensity $I$ of a wave is proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.For two waves with amplitudes $a_1$ and $a_2$,

Vedclass · Accepted Answer

$49:1$

Vedclass · Answer

(C) The intensity $I$ of a wave is proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.For two waves with amplitudes $a_1$ and $a_2$,the ratio of maximum intensity to minimum intensity is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{a_1 + a_2}{a_1 - a_2} \right)^2 = \left( \frac{\frac{a_1}{a_2} + 1}{\frac{a_1}{a_2} - 1} \right)^2$Given the ratio of amplitudes $\frac{a_1}{a_2} = \frac{4}{3}$,we substitute this into the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{\frac{4}{3} + 1}{\frac{4}{3} - 1} \right)^2 = \left( \frac{\frac{7}{3}}{\frac{1}{3}} \right)^2 = (7)^2 = \frac{49}{1}$Thus,the ratio of maximum and minimum intensity is $49:1$.

If the ratio of the amplitude of two waves is $4:3$,then the ratio of their maximum and minimum intensity is:

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