If the ratio of the areas of two squares is 9 | vedclass

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(C) Let the sides of the two squares be $x$ and $y$ respectively.The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Given the

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$3: 1$

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(C) Let the sides of the two squares be $x$ and $y$ respectively.The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Given the ratio of the areas is $\frac{x^2}{y^2} = \frac{9}{1}$.Taking the square root of both sides,we get $\frac{x}{y} = \sqrt{\frac{9}{1}} = \frac{3}{1}$.The perimeter of a square is given by the formula $	ext{Perimeter} = 4 	imes 	ext{side}$.The ratio of their perimeters is $\frac{4x}{4y} = \frac{x}{y}$.Substituting the value of $\frac{x}{y}$,the ratio of the perimeters is $3: 1$.

If the ratio of the areas of two squares is $9: 1$,then the ratio of their perimeters is

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