If the resistance of a conductor is 5,Omega a | vedclass

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(A) The formula for the temperature dependence of resistance is given by $R_{T_2} = R_{T_1}[1 + \alpha(T_2 - T_1)]$.Given values are $R_{T_1} = 5\,\Om

Vedclass · Accepted Answer

$0.008$

Vedclass · Answer

(A) The formula for the temperature dependence of resistance is given by $R_{T_2} = R_{T_1}[1 + \alpha(T_2 - T_1)]$.Given values are $R_{T_1} = 5\,\Omega$ at $T_1 = 50\,^{\circ}	ext{C}$ and $R_{T_2} = 7\,\Omega$ at $T_2 = 100\,^{\circ}	ext{C}$.Substituting these values into the equation:$7 = 5[1 + \alpha(100 - 50)]$$7 = 5[1 + 50\alpha]$$7 = 5 + 250\alpha$$2 = 250\alpha$$\alpha = \frac{2}{250} = \frac{1}{125} = 0.008\,^{\circ}	ext{C}^{-1}$.

If the resistance of a conductor is $5\,\Omega$ at $50\,^{\circ}\text{C}$ and $7\,\Omega$ at $100\,^{\circ}\text{C}$,then the mean temperature coefficient of resistance of the material is ............... $^{\circ}\text{C}^{-1}$.

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