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(A) The size of a nucleus is in the range of $10^{-15} \; m$ to $10^{-14} \; m$. The tip of a sharp pin is in the range of $10^{-5} \; m$ to $10^{-4}

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(A) The size of a nucleus is in the range of $10^{-15} \; m$ to $10^{-14} \; m$. The tip of a sharp pin is in the range of $10^{-5} \; m$ to $10^{-4} \; m$. To scale the nucleus to the size of a pin tip,we use a scaling factor of $10^{10}$ (since $10^{-15} 	imes 10^{10} = 10^{-5}$). The size of an atom is approximately $10^{-10} \; m$. Scaling the atom by the same factor of $10^{10}$,we get: $10^{-10} \; m 	imes 10^{10} = 1 \; m$. Therefore,if the nucleus is scaled to the size of a pin tip,the atom would be roughly $1 \; m$ in size.

If the size of a nucleus (in the range of $10^{-15} \; m$ to $10^{-14} \; m$) is scaled up to the tip of a sharp pin,what roughly is the size of an atom (in $; m$)? Assume the tip of the pin to be in the range $10^{-5} \; m$ to $10^{-4} \; m$.

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