If the solution boils at a temperature $T_1$ and the solvent at a temperature $T_2$,the elevation of boiling point is given by:

If $K_b$ denotes the molal elevation constant of water,then the boiling point of an aqueous solution containing $36 \ g$ of glucose (molar mass $= 180 \ g \ mol^{-1}$) per $dm^3$ is:

Calculate the molality of the solution containing a nonvolatile solute if the boiling point elevation of the solution is $0.39 \ K$.
[$K_{b}$ of water $= 0.52 \ K \ kg \ mol^{-1}$]

Calculate the molal elevation constant $(K_b)$ of a solvent if the boiling point of a $0.12 \ m$ solution is $319.8 \ K$ (Boiling point of pure solvent = $319.5 \ K$).

Which of the following statements is correct for the boiling point of a solvent containing a dissolved solid substance?

The boiling point of benzene is $353.23 \, K$. When $1.80 \, g$ of a nonvolatile solute was dissolved in $90 \, g$ of benzene,the boiling point is raised to $354.11 \, K$. The molar mass of the solute is $........ \, g \, mol^{-1}$. $[K_b \text{ for benzene} = 2.53 \, K \, kg \, mol^{-1}]$