If the specific conductance of $1 \, M \, H_2SO_4$ solution is $26 \times 10^{-2} \, S \, cm^{-1}$,then the equivalent conductivity would be

  • A
    $1.3 \times 10^2 \, S \, cm^2 \, eq^{-1}$
  • B
    $1.6 \times 10^2 \, S \, cm^2 \, eq^{-1}$
  • C
    $13 \, S \, cm^2 \, mol^{-1}$
  • D
    $1.3 \times 10^3 \, S \, cm^2 \, mol^{-1}$

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