If the statement pattern $(p \wedge q) \rightarrow (r \vee \sim s)$ is false,then the truth values of $p, q, r$ and $s$ are respectively:

For the given statement,identify the necessary and sufficient conditions.
$t:$ If you drive over $80 \, km/h$,then you will get a fine.

If $p, q, r$ are simple propositions with truth values $T, F, T$ respectively,then the truth value of $(\sim p \vee q) \wedge \sim r \Rightarrow p$ is

The equivalent form of the statement $\sim(p \rightarrow \sim q)$ is $ . . . . . . $

The maximum number of compound propositions,out of $p \vee r \vee s$,$p \vee \sim r \vee \sim s$,$p \vee \sim q \vee s$,$\sim p \vee \sim r \vee s$,$\sim p \vee \sim r \vee \sim s$,$\sim p \vee q \vee \sim s$,$q \vee r \vee \sim s$,$q \vee \sim r \vee \sim s$,$\sim p \vee \sim q \vee \sim s$ that can be made simultaneously true by an assignment of the truth values to $p, q, r$ and $s$,is equal to

If $\sim p \to q$ is false and $q \leftrightarrow r$ is false, then the truth value of $(p, q, r)$ is...