If the sum of the roots of the equation x^2 + | vedclass

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(C) Let the roots be $\alpha$ and $\beta$. From the relation between roots and coefficients,we have $\alpha + \beta = -p$ and $\alpha \beta = q$. Give

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$p^2 + p = 2q$

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(C) Let the roots be $\alpha$ and $\beta$. From the relation between roots and coefficients,we have $\alpha + \beta = -p$ and $\alpha \beta = q$. Given that the sum of the roots is equal to the sum of their squares: $\alpha + \beta = \alpha^2 + \beta^2$ We know that $\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta$. Substituting the values,we get: $-p = (-p)^2 - 2q$ $-p = p^2 - 2q$ Rearranging the terms,we get: $p^2 + p = 2q$.

If the sum of the roots of the equation $x^2 + px + q = 0$ is equal to the sum of their squares,then

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