If the surface tension of a soap solution is $3 \times 10^{-2} \,N/m$, then the work done in forming a soap film of $20 \,cm \times 5 \,cm$ will be
- A$6 \times 10^{-3} \,J$
- B$6 \times 10^{-4} \,J$
- C$6 \times 10^{-2} \,J$
- D$6 \,J$
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