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(B) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source and $T_

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$100$

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(B) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source and $T_2$ is the temperature of the sink.Given that the temperature of the sink is at absolute zero,we have $T_2 = 0 \ K$.Substituting this value into the efficiency formula:$\eta = 1 - \frac{0}{T_1} = 1 - 0 = 1$.To express the efficiency as a percentage,we multiply by $100$:$\eta = 1 	imes 100\% = 100\%$.Therefore,the efficiency of the Carnot engine is $100\%$.

If the temperature of the sink is at absolute zero,then the efficiency of the Carnot engine will be ........ $\%$

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