If the value of the discriminant of a quadratic equation $kx^2 - 6x + 1 = 0$ is $0$,then $k = \ldots$

$x=2$ is a solution of the equation $\ldots \ldots \ldots \ldots.$

Solve the following equation using the method of factorization: $6(2x+1)^2 - (2x+1) - 5 = 0$

State whether the quadratic equation $2 x^{2}+x-1=0$ has two distinct real roots. Justify your answer.

Write whether the following statements are true or false. Justify your answers.
$(i)$ If the coefficient of $x^{2}$ and the constant term have the same sign and if the coefficient of $x$ term is zero,then the quadratic equation has no real roots.
$(ii)$ Every quadratic equation has at least two roots.

If the roots of the following quadratic equation exist,find them by the method of completing the square: $x + \frac{2}{x} - 8 = 0$.