If the velocity at the maximum height of a pr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the initial velocity of the projectile be $u$ and the angle of projection be $	heta = 45^{\circ}$.At the maximum height, the vertical compone

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(B) Let the initial velocity of the projectile be $u$ and the angle of projection be $	heta = 45^{\circ}$.At the maximum height, the vertical component of velocity is $0$, so the velocity of the projectile is equal to its horizontal component: $v_{max} = u \cos 	heta$.Given $v_{max} = 20 \,m \,s^{-1}$ and $	heta = 45^{\circ}$, we have $20 = u \cos 45^{\circ} = u / \sqrt{2}$.Thus, $u = 20\sqrt{2} \,m \,s^{-1}$.The maximum height $H$ reached by a projectile is given by the formula $H = \frac{u^2 \sin^2 	heta}{2g}$.Substituting the values: $H = \frac{(20\sqrt{2})^2 \sin^2 45^{\circ}}{2 	imes 10}$.$H = \frac{800 	imes (1/\sqrt{2})^2}{20} = \frac{800 	imes 0.5}{20} = \frac{400}{20} = 20 \,m$.

If the velocity at the maximum height of a projectile projected at an angle of $45^{\circ}$ is $20 \,m \,s^{-1}$, then the maximum height reached by the projectile is (Acceleration due to gravity $=10 \,m \,s^{-2}$ ) (in $\,m$)

Similar Questions

$A$ ball is dropped from a high tower,and another ball is thrown horizontally from the same position. Which ball will reach the ground first?

$A$ projectile crosses two walls of equal height $H$ symmetrically as shown. The velocity of projection is........ $ms^{-1}$.

If the time of flight of a bullet over a horizontal range $R$ is $T \ s$,the inclination of the direction of projection to the horizontal is

For a given velocity,a projectile has the same range $R$ for two angles of projection. If $t_1$ and $t_2$ are the times of flight in the two cases,then:

$A$ particle is projected from the ground with a kinetic energy $E$ at an angle of $60^{\circ}$ with the horizontal. Its kinetic energy at the highest point of its motion will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module