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(B) According to Bohr's model,the velocity of an electron in a hydrogen-like species is given by the formula: $v_n = v_0 	imes \frac{Z}{n}$,where $Z$

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$0.5v$

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(B) According to Bohr's model,the velocity of an electron in a hydrogen-like species is given by the formula: $v_n = v_0 	imes \frac{Z}{n}$,where $Z$ is the atomic number and $n$ is the orbit number.For $He^{+}$,the atomic number $Z = 2$.In the first orbit $(n=1)$,the velocity is $v = v_0 	imes \frac{2}{1} = 2v_0$. Thus,$v_0 = \frac{v}{2}$.In the second orbit $(n=2)$,the velocity $v^{\prime}$ is given by: $v^{\prime} = v_0 	imes \frac{2}{2} = v_0$.Substituting the value of $v_0$ from the first step: $v^{\prime} = \frac{v}{2} = 0.5v$.

If the velocity of the revolving electron of $He^{+}$ in the first orbit $(n=1)$ is $v$,what is the velocity of the electron in the second orbit $(n=2)$?

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