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Question

(A) The energy $E$ of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given: $\lambda = 2000 \ \mathring{A} = 2000 	imes 10^{-8} \ cm = 2 \

Vedclass · Accepted Answer

$9.94 	imes 10^{-12}$

Vedclass · Answer

(A) The energy $E$ of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given: $\lambda = 2000 \ \mathring{A} = 2000 	imes 10^{-8} \ cm = 2 	imes 10^{-5} \ cm$.Speed of light $c = 3 	imes 10^{10} \ cm/s$.Planck's constant $h = 6.626 	imes 10^{-27} \ erg \ s$.Substituting the values: $E = \frac{6.626 	imes 10^{-27} \ erg \ s 	imes 3 	imes 10^{10} \ cm/s}{2 	imes 10^{-5} \ cm}$.$E = \frac{19.878 	imes 10^{-17}}{2 	imes 10^{-5}} \ erg = 9.939 	imes 10^{-12} \ erg \approx 9.94 	imes 10^{-12} \ erg$.

If the wavelength of an electromagnetic radiation is $2000 \ \mathring{A}$,what is its energy in ergs?

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