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(D) The pressure difference across a curved liquid surface is given by the Young-Laplace equation: $\Delta P = T \left( \frac{1}{r_1} + \frac{1}{r_2}

Vedclass · Accepted Answer

$\frac{T}{R}$

Vedclass · Answer

(D) The pressure difference across a curved liquid surface is given by the Young-Laplace equation: $\Delta P = T \left( \frac{1}{r_1} + \frac{1}{r_2} \right)$.For a cylindrical surface,one radius of curvature is $R$ (the radius of the cylinder) and the other radius of curvature is infinite $(r_2 = \infty)$ because the surface is straight along the length of the cylinder.Therefore,the excess pressure is $\Delta P = T \left( \frac{1}{R} + \frac{1}{\infty} \right) = T \left( \frac{1}{R} + 0 \right) = \frac{T}{R}$.Thus,the pressure in the water between the plates is lower than the atmospheric pressure by $\frac{T}{R}$.

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