(C) The original number is $3675249$.For each odd digit,subtract $2$: $3 - 2 = 1$$7 - 2 = 5$$5 - 2 = 3$$9 - 2 = 7$For each even digit,add $3$: $6 + 3

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(C) The original number is $3675249$.For each odd digit,subtract $2$: $3 - 2 = 1$$7 - 2 = 5$$5 - 2 = 3$$9 - 2 = 7$For each even digit,add $3$: $6 + 3 = 9$$2 + 3 = 5$$4 + 3 = 7$Replacing these digits in their original positions,the new number is $1953577$.In the new number $1953577$,the digits $5$ and $7$ appear twice each.Therefore,there are $2$ such digits.

Competitive Reasoning Series completion Series completion

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If $2$ is subtracted from each odd digit and $3$ is added to each even digit in the number $3675249$,how many digits will appear twice in the new number thus formed?

A
None
B
One
C
Two
D
Three

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If $2$ is subtracted from each odd digit and $3$ is added to each even digit in the number $3675249$,how many digits will appear twice in the new number thus formed?

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