If two soap bubbles of equal radii r coalesce | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When two soap bubbles of radii $r_1$ and $r_2$ coalesce,the radius of curvature $R$ of the common interface is given by the formula $\frac{1}{R} =

Vedclass · Accepted Answer

Infinity

Vedclass · Answer

(C) When two soap bubbles of radii $r_1$ and $r_2$ coalesce,the radius of curvature $R$ of the common interface is given by the formula $\frac{1}{R} = \frac{1}{r_1} - \frac{1}{r_2}$.Given that both bubbles have equal radii,$r_1 = r_2 = r$.Substituting these values into the formula: $\frac{1}{R} = \frac{1}{r} - \frac{1}{r} = 0$.Therefore,$\frac{1}{R} = 0$,which implies $R = \infty$.Thus,the interface between two bubbles of equal radii is a plane surface,and its radius of curvature is infinity.

If two soap bubbles of equal radii $r$ coalesce,then the radius of curvature of the interface between the two bubbles will be:

Similar Questions

If a section of a soap bubble of radius $r$ by a plane through its centre is considered,the force on the half due to surface tension is

$Assertion :$ $A$ bubble comes from the bottom of a lake to the top.
$Reason :$ Its radius increases.

The excess pressure inside a soap bubble of radius $2 \ cm$ is $50 \ dyne/cm^2$. The surface tension is

Pure water rises through a height $h$ in a capillary tube of internal radius $r$. Surface tension of water is $T$. The pressure difference between the water level in the container and the lowest point of the concave meniscus is

Two small drops of mercury each of radius $r$ coalesce to form a single large drop of radius $R$. The ratio of the total surface energies before and after the change is

Vedclass Test Series

Exam Paper Generator

Online Exam Module