If the vertex of a parabola is (2, -1) and th | vedclass

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(B) The distance from the vertex $(x_1, y_1)$ to the directrix $Ax + By + C = 0$ is given by $a = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$.Here,the

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$8$

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(B) The distance from the vertex $(x_1, y_1)$ to the directrix $Ax + By + C = 0$ is given by $a = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$.Here,the vertex is $(2, -1)$ and the directrix is $4x - 3y - 21 = 0$.Substituting these values,we get:$a = \frac{|4(2) - 3(-1) - 21|}{\sqrt{4^2 + (-3)^2}}$$a = \frac{|8 + 3 - 21|}{\sqrt{16 + 9}}$$a = \frac{|-10|}{5} = 2$The length of the latus rectum is $4a$.Therefore,the length of the latus rectum $= 4 	imes 2 = 8$.

If the vertex of a parabola is $(2, -1)$ and the equation of its directrix is $4x - 3y = 21$,then the length of its latus rectum is

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