Aniline xrightarrow[{{0^{circ}}C - {5^{circ}} | vedclass

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(D) The reaction of aniline with $NaNO_2/HCl$ at $0^{\circ}C - 5^{\circ}C$ is a diazotization reaction,which produces benzenediazonium chloride as int

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(D) The reaction of aniline with $NaNO_2/HCl$ at $0^{\circ}C - 5^{\circ}C$ is a diazotization reaction,which produces benzenediazonium chloride as intermediate $A$ $(Ph-N_2^+Cl^-)$.When benzenediazonium chloride $(A)$ reacts with $N,N$-dimethylaniline $(Ph-N(CH_3)_2)$,an electrophilic aromatic substitution reaction (coupling reaction) occurs.The diazonium cation acts as an electrophile and attacks the para-position of the $N,N$-dimethylaniline ring to form $p$-(dimethylamino)azobenzene,which is product $B$.The structure of $B$ is $Ph-N=N-C_6H_4-N(CH_3)_2$.

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

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Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$What is $B$?