The major product of the reaction is: R-CONH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction $R-CONH_2 \xrightarrow{NaOBr} R-NH_2$ is the Hofmann bromamide degradation reaction. In this reaction,the alkyl or aryl group $R$ mig

Vedclass · Accepted Answer

Vedclass · Answer

(A) The reaction $R-CONH_2 \xrightarrow{NaOBr} R-NH_2$ is the Hofmann bromamide degradation reaction. In this reaction,the alkyl or aryl group $R$ migrates from the carbonyl carbon to the nitrogen atom. This migration occurs with complete retention of configuration at the chiral center of the $R$ group. Since the starting material has the $Ph$ group at the top,$CH_3$ on the left,$H$ at the bottom,and the $CONH_2$ group on the right,the resulting amine $R-NH_2$ will have the $NH_2$ group in the same position as the original $CONH_2$ group,with all other groups $(Ph, CH_3, H)$ remaining in their respective positions. Comparing this with the given options,the structure in image $817-$a132 represents the correct product with retained configuration.

The major product of the reaction is:
$R-CONH_2 \xrightarrow{NaOBr} (A)$
(where $R$ is the chiral group shown in the image)

Similar Questions

The major product $(R)$ of the following reaction is:
Aniline $\xrightarrow[{pyridine}]{{CH_3COCl}}$ $P$ $\xrightarrow[{CH_3COOH}]{{Br_2}}$ $Q$ $\xrightarrow{{{H_3O^{+}}}}$ $R$

Consider the following reaction sequence and identify the correct option:

Which of the following is the most acidic substance?

Identify products $I$ and $II$ in the following reactions: $Aniline \xrightarrow{COCl_2} I$ and $Aniline \xrightarrow{C_2H_5MgI} II$.

Which of the following statements is true for Benzenediazonium fluoroborate?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The major product of the reaction is: $R-CONH_2 \xrightarrow{NaOBr} (A)$ (where $R$ is the chiral group shown in the image)