In $BF_3$ molecule:
- Aall the $B-F$ bonds are single covalent in nature.
- Bthe boron-fluorine bond has some double bond character and this bond is delocalized.
- Cthe bond energy and bond length of the $B-F$ bond indicate its single bond character.
- Dall the bonds are ionic.
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Similar Questions
What is the bond order of the carbon-carbon bond in benzene?
Easy
View SolutionResonance structures of a molecule do not have:
MediumIIT 1984
View SolutionThe stability order of the following resonance structures is:
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$
Draw the resonance structures for the following compounds. Show the electron shift using curved-arrow notation.
$(a)$ $C_{6}H_{5}OH$
$(b)$ $C_{6}H_{5}NO_{2}$
$(c)$ $CH_{3}CH=CH-CHO$
$(d)$ $C_{6}H_{5}CHO$
$(e)$ $C_{6}H_{5}CH_{2}^{+}$
$(f)$ $CH_{3}CH=CH-CH_{2}^{+}$
$(a)$ $C_{6}H_{5}OH$
$(b)$ $C_{6}H_{5}NO_{2}$
$(c)$ $CH_{3}CH=CH-CHO$
$(d)$ $C_{6}H_{5}CHO$
$(e)$ $C_{6}H_{5}CH_{2}^{+}$
$(f)$ $CH_{3}CH=CH-CH_{2}^{+}$
Medium
View SolutionThe correct statement$(s)$ about $O_3$ is (are)
$A$. $O-O$ bond lengths are equal.
$B$. Thermal decomposition of $O_3$ is endothermic.
$C$. $O_3$ is diamagnetic in nature.
$D$. $O_3$ has a bent structure.
$A$. $O-O$ bond lengths are equal.
$B$. Thermal decomposition of $O_3$ is endothermic.
$C$. $O_3$ is diamagnetic in nature.
$D$. $O_3$ has a bent structure.
DifficultIIT 2013
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