In XeO_3F_2,the number of bond pair(s),pi-bon | vedclass

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Question

(A) The central atom $Xe$ has $8$ valence electrons.In $XeO_3F_2$,$Xe$ forms $3$ double bonds with $3$ oxygen atoms and $2$ single bonds with $2$ fluo

Vedclass · Accepted Answer

$5, 3, 0$

Vedclass · Answer

(A) The central atom $Xe$ has $8$ valence electrons.In $XeO_3F_2$,$Xe$ forms $3$ double bonds with $3$ oxygen atoms and $2$ single bonds with $2$ fluorine atoms.Total bond pairs = $3$ (from $Xe=O$) + $2$ (from $Xe-F$) = $5$.Number of $\pi$-bonds = $3$ (each $Xe=O$ bond contains one $\pi$-bond).Number of lone pairs on $Xe$ = $\frac{1}{2} 	imes (8 - 5 - 3) = 0$.Thus,the number of bond pairs,$\pi$-bonds,and lone pairs are $5, 3, 0$ respectively.

In $XeO_3F_2$,the number of bond pair$(s)$,$\pi$-bond$(s)$ and lone pair$(s)$ on $Xe$ atom respectively are:

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