In N_2 molecule,the atoms are bonded by | vedclass

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(A) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$.To complete its octet,each nitrogen atom shares $3$ electrons with another nitr

Vedclass · Accepted Answer

$1$ $\sigma$,$2$ $\pi$

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(A) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$.To complete its octet,each nitrogen atom shares $3$ electrons with another nitrogen atom,forming a triple bond $(N \equiv N)$.$A$ triple bond consists of $1$ $\sigma$ bond (formed by head-on overlap of $p_z$ orbitals) and $2$ $\pi$ bonds (formed by lateral overlap of $p_x$ and $p_y$ orbitals).Therefore,the $N_2$ molecule contains $1$ $\sigma$ and $2$ $\pi$ bonds.

In $N_2$ molecule,the atoms are bonded by

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