In $[Cu(NH_3)_4]SO_4$,$Cu$ has the following hybridization:

  • A
    $dsp^2$
  • B
    $sp^3$
  • C
    $sp^2$
  • D
    $sp^3d^2$

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Similar Questions

Which of the following complexes does not exhibit $d^2sp^3$ hybridization?

Identify the $CORRECT$ set of details from the following:
$A$. $[Co(NH_{3})_{6}]^{3+}$: Inner orbital complex; $d^{2}sp^{3}$ hybridized
$B$. $[MnCl_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$C$. $[CoF_{6}]^{3-}$: Outer orbital complex; $d^{2}sp^{3}$ hybridized
$D$. $[FeF_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$E$. $[Ni(CN)_{4}]^{2-}$: Inner orbital complex; $sp^{3}$ hybridized
Choose the correct answer from the options given below:

What is the type of magnetic behavior and geometry respectively in Cuproammonium sulphate (Atomic no. of $Cu=29$)?

Which of the following is not a square planar complex?

Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The types of hybridisation of $Ni$ in these complexes are . . . . . . and . . . . . . respectively.

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