In BrF_3 molecule,the lone pairs occupy equat | vedclass

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Question

(A) In $BrF_3$,the central atom $Br$ has $7$ valence electrons. It forms $3$ $Br-F$ bonds and has $2$ lone pairs,resulting in a total of $5$ electron

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Lone pair-lone pair repulsion and lone pair-bond pair repulsion

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(A) In $BrF_3$,the central atom $Br$ has $7$ valence electrons. It forms $3$ $Br-F$ bonds and has $2$ lone pairs,resulting in a total of $5$ electron pairs ($sp^3d$ hybridization).According to $VSEPR$ theory,lone pairs prefer equatorial positions in a trigonal bipyramidal geometry to minimize lone pair-lone pair repulsion and lone pair-bond pair repulsion.By placing both lone pairs in equatorial positions,the $90^{\circ}$ lone pair-lone pair interactions are avoided,which significantly reduces the overall repulsion in the molecule.

In $BrF_3$ molecule,the lone pairs occupy equatorial positions to minimize

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