In [Pt(NH_3)_2Cl_2],the Pt-Cl bond length is | vedclass

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(C) The complex $[Pt(NH_3)_2Cl_2]$ exhibits square planar geometry.For a square planar complex with bond length $d = 2 \ \mathring{A}$,the distance be

Vedclass · Accepted Answer

cis-square planar

Vedclass · Answer

(C) The complex $[Pt(NH_3)_2Cl_2]$ exhibits square planar geometry.For a square planar complex with bond length $d = 2 \ \mathring{A}$,the distance between adjacent $Cl$ atoms (cis-position) is $d\sqrt{2} = 2 	imes 1.414 = 2.828 \ \mathring{A} \approx 2.88 \ \mathring{A}$.The distance between opposite $Cl$ atoms (trans-position) would be $2d = 2 	imes 2 = 4 \ \mathring{A}$.Since the given $Cl-Cl$ distance is $2.88 \ \mathring{A}$,which corresponds to the cis-configuration,the complex is cis-square planar.Hence,the correct option is $C$.

List-$I$	List-$II$
$A. \, Ni(CN)_5^{3-}$	$1. \, sp^3$
$B. \, CuCl_5^{3-}$	$2. \, dsp^2$
$C. \, AuCl_4^-$	$3. \, sp^3d_{z^2}$
$D. \, ClO_4^-$	$4. \, d_{x^2-y^2}sp^3$

In $[Pt(NH_3)_2Cl_2]$,the $Pt-Cl$ bond length is $2 \ \mathring{A}$ and the $Cl-Cl$ distance is $2.88 \ \mathring{A}$. What is the geometry of the compound?

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