In $NH_4NO_2$,the oxidation number of nitrogen will be

  • A
    $3$
  • B
    $5$
  • C
    $-3$ and $+3$
  • D
    $+3$ and $+5$

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Similar Questions

The oxidation number of sulphur is $-4$ in

Calculate the oxidation number of sulphur,chromium,and nitrogen in $H_2SO_5$,$Cr_2O_7^{2-}$,and $NO_3^-$. Suggest the structures of these compounds and explain the fallacy in the calculated oxidation number for $H_2SO_5$.

$A$ compound contains atoms of $x, y$ and $z$ elements. Oxidation numbers of $x, y$ and $z$ are $+3, +5$ and $-2$ respectively. Identify the possible formula of this compound?

Match the following compounds with their respective oxidation numbers of the central atom or specific element:
Compound Oxidation number
$1$. $C_2H_6$ $a$. $+3$
$2$. $H_2O_2$ $b$. $+6$
$3$. $LiAlH_4$ $c$. $-3$
$4$. $HO_2^-$ $d$. $-1$
$5$. $PbSO_4$ $e$. $+1$

Sulphur has the highest oxidation state in

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