In XeF_2,the hybridisation of Xe is: | vedclass

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(B) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ single bonds with $F$ atoms,using $2$ electrons.The remaining $6$ electr

Vedclass · Accepted Answer

$sp^3d$

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(B) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ single bonds with $F$ atoms,using $2$ electrons.The remaining $6$ electrons form $3$ lone pairs.The steric number is calculated as: $	ext{Steric Number} = 	ext{Number of bond pairs} + 	ext{Number of lone pairs} = 2 + 3 = 5$.$A$ steric number of $5$ corresponds to $sp^3d$ hybridisation.

In $XeF_2$,the hybridisation of $Xe$ is:

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