In 1 g of a metal oxide,the mass of metal pr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Mass of metal oxide = $1 \ g$ Mass of metal = $0.68 \ g$ Mass of oxygen = $1 \ g - 0.68 \ g = 0.32 \ g$ According to the law of equivalence,the nu

Vedclass · Accepted Answer

$17$

Vedclass · Answer

(A) Mass of metal oxide = $1 \ g$ Mass of metal = $0.68 \ g$ Mass of oxygen = $1 \ g - 0.68 \ g = 0.32 \ g$ According to the law of equivalence,the number of equivalents of metal equals the number of equivalents of oxygen. $\frac{	ext{Mass of metal}}{	ext{Equivalent weight of metal}} = \frac{	ext{Mass of oxygen}}{	ext{Equivalent weight of oxygen}}$ $\frac{0.68}{E} = \frac{0.32}{8}$ $E = \frac{0.68 	imes 8}{0.32} = \frac{5.44}{0.32} = 17$ Therefore,the equivalent weight of the metal is $17$.

In $1 \ g$ of a metal oxide,the mass of metal precipitated is $0.68 \ g$. What is the equivalent weight of the metal?

Similar Questions

The equivalent weight of an element is $4$. Its chloride has a $V.D$ of $59.25$. Then the valency of the element is:

$1 \ g$ of hydrogen combines with $80 \ g$ of bromine. $1 \ g$ of calcium (valency $= 2$) combines with $4 \ g$ of bromine. The equivalent weight of calcium is ...

Chlorine has two isotopes $^{35}Cl$ and $^{37}Cl$ with an average atomic mass of $35.5$. What is the ratio of their relative abundance respectively?

The equivalent weight of a metal is $4.5$ and the molecular weight of its chloride is $80$. The atomic weight of the metal is

The equivalent weight of a certain trivalent element is $20$. The molecular weight of its oxide is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module